Answer:
630 Hz.
Explanation:
As we are considering the one end open pipe. So for the sound wave there will be a pressure node at the open end of the tube as at that place the molecules can not move back and forth. However on the closed end there will be a flow node as the water molecules their are moving back and forth. So it will produces the resonance at the positions 1/4, 3/4.......
we can find the wavelength by multiplying the levels distance by 2.
λ = 2 × 0.27 m = 0.54
f = Vs/λ
= 340/0.54
= 630 Hz
