lennys34 lennys34

21-01-2020
Physics

contestada

How fast must a 70 kg student be running to have a kinetic energy of 568 J?!

Respuesta :

ednorobello92 ednorobello92

21-01-2020

Answer: 4.03 m/s

Explanation: Kinetic energy is

KE = 1/2 m v²

So we derive the equation to have v.

v = √ 2KE / m

= 2 x 568 J / 70 kg

= 16.23

= √ 16.23

= 4.03 m/s

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