Answer:
The net charge on the object is 0.1328 μC.
Explanation:
Given that,
Proton [tex]P=5.54\times10^{12}[/tex]
Electron [tex]e=4.71\times10^{12}[/tex]
We need to calculate the net charge on the object
Using formula of net charge
[tex]Q=p+e[/tex]
Where, Q = net charge
p = protons
e = electron
Put the value into the formula
[tex]Q =(5.54-4.71)\times10^{12}\times1.6\times10^{-19}[/tex]
[tex]Q=1.328\times10^{-7}\ C[/tex]
[tex]Q=0.1328\times10^{-6}\ C[/tex]
[tex]Q=0.1328\ \mu C[/tex]
Hence, The net charge on the object is 0.1328 μC.
