Answer:
Molarity: [tex]M=6.095 M[/tex]
Explanation:
Base of calculation: 100 g of solution
Ammount of solute: [tex]W=0.2*100 g=20 g[/tex]
Moles of solute: [tex]n=\frac{W}{m}=\frac{20 g}{40 g/mol}=0.5 mol[/tex]
Solution volume: [tex]V=\frac{100 g}{d}=\frac{100 g}{1.219 g/cm^3}[/tex]
[tex]V=82.03 cm^3=0.08203 L[/tex]
Molarity: [tex]M=\frac{n}{V}=\frac{0.5 mol}{0.08203 L}=6.095 M[/tex]
