Answer:
EF = 28.
Step-by-step explanation:
If two triangles Δ ABC and Δ DEF are similar, then the ratio of the lengths of corresponding sides of Δ ABC and Δ DEF will be constant.
Therefore, we can write
[tex]\frac{AB}{DE} = \frac{BC}{EF} = \frac{CA}{FD}[/tex] .............. (1)
Now, AB, BC, and DE are given to be 5, 8, and 17.5
And we have to find the length of EF.
So, from equation (1), we get
[tex]\frac{5}{17.5} = \frac{8}{EF}[/tex]
⇒ [tex]EF = 8 \times \frac{17.5}{5} = 28[/tex]. (Answer)
