Answer:
Both of them will hit the water at the same time.
Explanation:
The time taken to hit the water is given by:
Let H be the height of the bridge.
[tex]H=ut+\frac{1}{2}gt^{2}\\\\Initial\:Velocity=u=0\\\\H=\frac{1}{2}gt^{2}\\\\t=\sqrt{2gH}[/tex]
The time taken to hit the water does not depend on the weight of the object.
It only depends on the height of the bridge.
Since, both the objects are dropped from the same bridge, they will hit the water at the same time.
