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The amount of potential energy in 1 glucose molecule = 2805kJ/mol. The amount of energy in 1 ATP molecule = 30.5kJ/mol. In a human skeletal muscle cell, 36 molecules of ATP are made for every 1 molecule of glucose burned. What is the efficiency of the aerobic respiration pathway?

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princessesther2011

Answer:The efficiency of the aerobic respiration pathway is 39.1%

Explanation:

Efficiency = (Energy output÷Energy input) × 100

Energy output = Amount of energy in 36 ATP molecules = 36 × Amount of energy in 1 ATP molecule = 36×30.5KJ/mol = 1098KJ/mol

Energy input = Amount of potential energy in 1 molecule of glucose burned which is 2805KJ/mol

Efficiency =(1098KJ/mol ÷ 2805KJ/mol) × 100 = 39.1%

Efficiency of the aerobic respiration pathway is 39.1%