Answer:
P(O) = 0.74 atm
Explanation:
Given data:
Amount of oxygen = 27%
Amount of second gas = X = 100-27 = 73%
Total pressure = 2.0 atm
Partial pressure of oxygen = ?
Solution:
Moles of oxygen = 27/100 = 0.27 mol
Moles of X = 73/100 = 0.73 mol
Partial pressure of oxygen:
P(O) = [n₁/ nt] P(total)
n₁ = moles of oxygen
nt = total number of moles (0.27 + 0.73)
P(O) = [n₁/ nt] P(total)
P(O) = [0.27/ 0.73] 2.0 atm
P(O) = 0.37 × 2.0 atm
P(O) = 0.74 atm
