Answer:
29 and 20 are such integers.
Step-by-step explanation:
Let one of the two integers = m
let other integer = n
Now, since sum of two integers = 49
⇒ m + n = 49 ............ (1)
The difference of two integers = 9
⇒ m - n = 9 ................ (2)
Solving both the equations:
Add equations (1) and (2) , we get
2 m = 58
or, m = 58 / 2 = 29
or, m = 29
So, one of the integers = m = 29
Now, the other integer is n = 49 - m = 49 - 29 = 20
or, n = 29
Hence, 20 and 29 are such integers.
