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16-11-2019
Mathematics

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Find the roots of the equation: 2(x−3)^2=3·(2x−11)

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KurdishPotato KurdishPotato

16-11-2019

Answer:

5 and 4

Step-by-step explanation:

2(x-3)^2➡ 2×(x^2-6x+9) ➡ 2x^2-12x+18 = 6x-22

transfer and add like terms

2x^2-12x-6x=-22-18

2x^2-18x = -40

2x^2 - 18x + 40 = 0

(2x-8)(x-5)

x = 5 or, x = 8/2 ➡ 4

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