Answer:
[tex]10^{9}\ \mu L[/tex]
Explanation:
Considering
[tex]Molarity_{1}\times Volume_{1}=Molarity_{2}\times Volume_{2}[/tex]
Given that:
[tex]Molarity_{1}=1.0\ M[/tex] (let)
[tex]Volume_{1}=1000\ mL[/tex]
[tex]Volume_{2}=?[/tex]
[tex]Molarity_{2}=0.001\ M[/tex]
So,
[tex]1.0\times 1000=0.001\times Volume_{2}[/tex]
Volume = 10⁶ mL
[tex]1\ mL=10^{3}\ \mu L[/tex]
So, Volume = [tex]10^{9}\ \mu L[/tex]
