Respuesta :

olemakpadu
(x + 2)¹⁰

Would take the terms in reducing powers of x, and increasing powers of 2.


1st term =        ¹⁰C₀ x¹⁰(2)⁰        = x¹⁰

Second term =  ¹⁰C₁ x¹⁰⁻¹(2)¹      =  ¹⁰C₁ x⁹(2)¹

Third term =    ¹⁰C₂ x¹⁰⁻²(2)²        =  ¹⁰C₂ x⁸(2)² 

Fourth term =  ¹⁰C₃ x¹⁰⁻³(2)³        =  ¹⁰C₃ x⁷(2)³


So we shall now simplify the fourth term which is = ¹⁰C₃ x⁷(2)³

ⁿCr = n! /( r!(n -r)! )

¹⁰C₃ = 10! /( 3!(10 -3)! ) = 10! / (3!*7!) =  (10 *9 * 8* 7!) / (3!*7!)

        =     10*9*8 / 3! = (10*9*8) / (3*2*1) = 120  


4th term = ¹⁰C₃ x⁷(2)³ = 120 *x⁷*(2)³ = 120*2³*x⁷

             = 120*8x⁷

             = 960x⁷

So the fourth term in reducing powers of x = 960x⁷

I hope this helped.

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