gabby6585
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  • 20-09-2019
  • Mathematics
contestada

Which shows how the distributive property can be used to evaluate
56 x 3® 1568 - 3139
13
585

Respuesta :

Аноним Аноним
  • 20-09-2019

Answer:Hello,

Let's assume

a the lowest number

b the tallest.

HCF(a,b)=56

LCM(a,b)=1568

a*b=HCF*LCM=(2^5*7^2)*(2^3*7)=2^8*7^3

a=56*x

b=56*y

a*b=56²*x*y==>x*y=2^2*7

The numbers possible are (56*1,56*28),(56*2,56*14),(56*4,56*7)

(56*1,56*28)=(56,1568) is excluded.

(56*2,56*14)=(112,784) has like HCF=112 and not 56.

The answer is (56*4,56*7)=(224,392) which HCF is 56 and LCM=1568.

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