Answer:
The distance between the slits is 3.55 μm
Explanation:
Given that,
Order number = 3
Wave length = 610 nm
Angle = 31°
We need to calculate the distance between the slits
Using formula of distance of slit
[tex]d\sin\theta=n\lambda[/tex]
[tex]d=\dfrac{n\lambda}{\sin\theta}[/tex]
Where, n = order number
[tex]\lambda[/tex]= wavelength
Put the value into the formula
[tex]d=\dfrac{3\times610\times10^{-9}}{\sin31}[/tex]
[tex]d=3.55\times10^{-6}\ m[/tex]
[tex]d= 3.55\ \mu m[/tex]
Hence, The distance between the slits is 3.55 μm.
