Answer:
21 °C
Explanation:
Heat generated by bulb in one second, H = 95 W
Radius = 3 cm = 0.03 m, Area = 3.14 x 0.03 x 0.03 = 2.826 x 10^-3 m^2
Thickness, d = 0.5 mm = 0.5 x 10^-3 m
Coefficient of thermal conductivity of glass, K = 0.8 W/mK
Let ΔT be the temperature difference between inner and outer surface.
H = K A ΔT / d
95 = 0.8 x 2.826 x 10^-3 x ΔT / (0.5 x 10^-3)
ΔT = 21 °C
Thus, the temperature difference between the inner and outer surface of the bulb is 21 °C.
