Answer:
[tex]9.42\ ft^{2}[/tex]
Step-by-step explanation:
step 1
Find the surface area of one hanging lantern
we know that
The surface area of a cone (hanging lantern) is equal to
[tex]SA=\pi r^{2} +\pi rl[/tex]
we have
[tex]r=0.5\ ft[/tex]
[tex]l=1.5\ ft[/tex]
assume
[tex]\pi=3.14[/tex]
substitute the values
[tex]SA=(3.14)(0.5)^{2} +(3.14)(0.5)(1.5)[/tex]
[tex]SA=3.14\ ft^{2}[/tex]
step 2
Find the surface area of the three hanging lanterns
[tex]SA=(3)*3.14=9.42\ ft^{2}[/tex]
