Answer:
[tex]1.74\cdot 10^{-3}rad/s[/tex]
Explanation:
The angular velocity of the hour hand is given by:
[tex]\omega=\frac{2 \pi}{T}[/tex]
where
[tex]2 \pi[/tex] is the angular displacement (in radians) corresponding to one complete rotation
T is the period of the hour hand (the time it takes to complete one rotation)
The period of the hour hand is 1 hour, which is
[tex]T=1 h=3600 s[/tex]
So the angular velocity is
[tex]\omega=\frac{2 \pi}{3600 s}=1.74\cdot 10^{-3}rad/s[/tex]
