TheChillWalrus
TheChillWalrus TheChillWalrus
  • 21-04-2016
  • Mathematics
contestada

[tex]g(x)=x^3+2x-1[/tex].

texgxx32x1tex class=

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kiev001
kiev001 kiev001
  • 21-04-2016
First you differentiate it. So:
x^3 + 2x - 1 = 3x^2 + 2
at point (2, 1) the x value is 2 so you substitute that into the differentiated equation.
you get 3(2)^2 + 2 = 14
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