lolokie666 lolokie666
  • 20-03-2019
  • Mathematics
contestada

according to the fundamental theorem of algebra, how many zeros does the function f(x)=17x^15+41x^12+13x^3-10 have?​

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tramserran
tramserran tramserran
  • 20-03-2019

Answer:  15

Step-by-step explanation:

The total number of zeros (which includes real & complex roots) is the degree of the function. The degree of a function is the biggest exponent.

f(x) = 17x¹⁵ + 41x¹² + 13x³ - 10

has a degree of 15, so the function has 15 zeros.

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