samueltaye
samueltaye samueltaye
  • 18-03-2019
  • Mathematics
contestada


[tex]f(x) = e ^{2x} \sin(x \: ) \: then \:its \: \: second \: derivatives \: \: is[/tex]

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znk
znk znk
  • 18-03-2019

Answer:

See below  

Step-by-step explanation:

Here are some standard derivatives we will be using:

ƒ(x)   ⟶  f'(x)    

sin(x)  ⟶  cos(x)

cos(x) ⟶ -sin(x)

[tex]e^{ax} \longrightarrow ae^{ax}[/tex]

gh     ⟶ gh' + hg'

[tex]f(x) = e^{2x}\sin(x)\\f'(x) = e^{2x}\cos(x) + 2e^{2x}\sin(x) \\f''(x)=-e^{2x}\sin(x) + e^{2x}\cos(x)+2e^{2x}\cos(x) + 4e^{2x}\sin(x)[/tex]

[tex]f''(x)= 4e^{2x}\cos(x)+ 3e^{2x}\sin(x)[/tex]

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