Answer: The solution is two distinct real zeros.
Step-by-step explanation:
Subtract 6 from both sides:
[tex]x^2-3x-6=6-6\\x^2-3x-6=0[/tex]
Calculate the discriminant:
[tex]D=b^2-4ac[/tex]
Where:
a=1
b=-3
c=-6
Then:
[tex]D=(-3)^2-4(1)(-6)=33[/tex]
By definition, when [tex]D>0[/tex] the solution is two distinct real zeros.
