Answer:
(⅛)a^(15 - 3m)
Step-by-step explanation:
[8a^(m+3)]³[¼a^(1 - m)]⁶ a^(x+y) = (a^x)(a^y)
= [8(a^m)a³]³[¼a·a^(-m)]⁶ (a^x)^y = a^(xy)
= 8³a^(3m)a⁹ × (¼)⁶a⁶a^(-6m) Associate like terms
= (8³/4⁶)a¹⁵a^(-3m)
= (2×4)³/4⁶a^(15 - 3m)
= 2³× 4³/4⁶a^(15 - 3m)
= 2³×(1/4³) a^(15 - 3m)
= 2³ × (1/(2²)³ a^(15 - 3m)
= 2³/2⁶a^(15 - 3m)
= (½)³a^(15 - 3m)
= (⅛)a^(15 - 3m)
