Answer:
c
Step-by-step explanation:
using the law of logarithms
log[tex]x^{n}[/tex] ⇔ nlogx
given 17 + [tex]e^{7x}[/tex] = 33 ( subtract 17 from both sides )
[tex]e^{7x}[/tex] = 16 ( take the ln of both sides )
ln[tex]e^{7x}[/tex] = ln16
7xlne = ln16 ← lne= 1
7x = ln16 ( divide both sides by 7 )
x = [tex]\frac{ln16}{7}[/tex] → c
Answer:
hello :
e^7x = 33 - 17
e^7x = 16
7x = ln16
x= ln16/7 .... ( answer : c )
