wfz
wfz wfz
  • 18-01-2019
  • Mathematics
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gmany
gmany gmany
  • 18-01-2019

m∠JKL = m∠DKL + m∠JKD

We have m∠JKL = 2x + 141,  m∠DKL = x + 56 and m∠JKD = 85°. Substitute:

2x + 141 = x + 56 + 85

2x + 141 = x + 141        subtract 141 from both sides

2x = x       subtract x from both sides

x = 0

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