Answer:
14th answer is [tex]x=\sqrt{288} \\ x= -\sqrt{288}[/tex]
15th answer is [tex]xy^{2} \sqrt{5}[/tex]
Step-by-step explanation:
14)
triangle is a right triangle, the legs will have the same measure
let the legs be x
x^2 + x^2 = 24^2
2x^2 = 576
x^2 = 288
[tex]x=\sqrt{288} \\ x= -\sqrt{288}[/tex]
15)
[tex]area of the circle[/tex][tex]=\pi r^{2}[/tex]
[tex]5x^{2} y^{4} \pi =\pi r^{2} \\ r^{2} =5x^{2} y^{4} \\ r\sqrt{5x^{2} y^{4} } \\ r=\sqrt{5} xy^{2}[/tex]
