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  • 17-12-2018
  • Mathematics
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help me on this problem

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  • 30-12-2018

[tex](a)\\\\\triangle HFG\sim\triangle HGE\sim\triangle GFE\\\\(b)\\\\\dfrac{FE}{GE}=\dfrac{GE}{HE}\qquad\qquad\dfrac{HF}{HG}=\dfrac{HG}{HE}[/tex]

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