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if the volume of a gas contracted from 648 mL to 0.15L, what was its final pressure if it started at a pressure of 485 kpa

Respuesta :

znk

Answer:

2100 kPa

Explanation:

The temperature is constant, so the only variables are pressure and volume.

We can use Boyle’s Law.

p₁V₁ = p₂V₂     Divide both sides of the equation by V₂

p₂ = p₁ × V₁/V₂  

p₁ = 485 kPa; V₁ =              648 mL  

p₂ = ?;            V₂ = 0.15 L = 150 mL      Calculate p₂

p₂ = 485 × 648/150

p₂ = 2100 kPa