Answer: The equivalent resistance in this circuit [tex]15\Omega[/tex]
Explanation:
In the given circuit, resistors are arranged in series,so the equivalent resistance in the circuit will be given as:
[tex]R_1=2.0 \Omega,R_2=3.0 \Omega,R_3=4.0 \Omega,R_4=6.0\Omega[/tex]
[tex]R_{eq}=R_1+R_2+R_3+R_4[/tex]
[tex]R_{eq}=2.0\Omega+3.0\Omega+4.0\Omega+6.0\Omega=15\Omega[/tex]
The equivalent resistance in this circuit [tex]15\Omega[/tex]
