qveenchantell qveenchantell

18-10-2018
Mathematics

contestada

4(r+20)=1/5 (20r +400)

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konrad509 konrad509

18-10-2018

[tex]4(r+20)=\dfrac{1}{5}(20r+400)\\\\4r+80=4r+80\\\\0=0\\\\r\in\mathbb{R}[/tex]

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