Respuesta :

znk

The mass of 0.699 mol of C₆H₁₂O₆ is 126 g.

Mass = 0.699 mol × (180.16 g/1 mol) = 126 g

Giangiglia

Answer:

[tex]m_{gluc}=125.82g[/tex]

Explanation:

Hi, first you need to calculate the molecular weight of the glucose:

Knowing that the atomic weights are:

C=12

H=1

O=16

[tex]Mr_{gluc}=6*12+12+6*16[/tex]

[tex]Mr_{gluc}=180[/tex]

By definition the Mr is the weight in grams of 1 mol of the sustance. So:

[tex]m_{gluc}=\frac{180g}{mol}*0.699mol[/tex]

[tex]m_{gluc}=125.82g[/tex]

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