javierbaptistapeupgh
javierbaptistapeupgh
19-09-2018
Mathematics
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Need the answer plisssss
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choixongdong
choixongdong
19-09-2018
Sum of cubes"
-27a^3b^6 + 8a^9b^12
= (-3ab^2)^3 + (2a^3b^4)^3
Answer is the first one
-27a^3b^6 + 8a^9b^12
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