JoshuaXYP7977 JoshuaXYP7977
  • 17-09-2018
  • Physics
contestada

A sheet of gold foil has a volume of 0.750 cm3. If the foil measures 50.0cm by 10.0cm, what is the thickness of the foil?

Respuesta :

albelicat albelicat
  • 26-09-2018

To calculate the thickness of foil, we use formula of volume as

[tex]V= l w t[/tex]

Here, l is the length of the foil, w is the width of the foil and t is the thickness of the foil.

Given,  [tex]V = 0.750 \ cm^3[/tex], [tex]l = 50 cm[/tex] and [tex]w = 10 \ cm[/tex].

Substituting theses values in above equation, we get

[tex]0.750 \ cm^3 = 50 cm \times 10 \ cm \times t \\\\ t =  0.0015 cm[/tex]

Thus, the thickness of the foil is 0.0015 cm.

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