To find the volume,we would first need to find the height of square pyramid, by it's base edge and slant height using Pythagoras theorem:
[tex]{height }^{2} = {13}^{2} - {10}^{2} \\ {height }^{2} = 69 \\ height = \sqrt{69} [/tex]
We can then use the pyramid formula to find the volume:
[tex]base \: \times \: height \: \times \frac{1}{3} [/tex]
In this case,the volume will be:
10×_/69×1/3
=27.68874...
≈27.7 units^3
Hope it helps!
