The POH of a 2.70 x10^-11 solution of lithium hydroxide(LiOH) is 10.6
calculation
POH= -log (OH-)
write the equation for dissociation of LiOH
LiOh---> Li^+(aq) + OH-(aq)
from the equation above the ratio LiOH: OH is 1:1 therefore the concentration of OH- =2.70 x10 ^-11
that is - log (2.70 x10^-11) = 10.6
