First we have to find the slopes and the points are (-3,4) ,(0,-2) .
[tex] Slope = \frac{-2-4}{0-(-3)} [/tex]
[tex] slope = \frac{-6}{3}=-2 [/tex]
Slope of parallel lines are equal. Therefore the slope of the required line is -2 too .
Using slope intercept form which is
y=m x+b
We have point (-5,2) and slope, m =-2
Substituting the values of x,y and m
2 = -2(-5)+b
2 = 10 + b
Subtracting 10
-8 = b
So we have slope = -2 and y intercept, b=-8. THerefore required equation of line is
y=-2x-8.
