The rate of a reaction is = 0.12 mol.L^-1.S^-1
when we have K = 1 x 10^-2
[A] = 2 M & [B] = 3M
m= 2 & i = 1
So when the rate = K[A]^m [B]^i
When we have m + i = 3 so the order of this reaction is 3 So the unit of K is L^2.mol^-2S^-1
So by substitution:
Therfore the rate = (1x 10 ^-2 L^-2.mol^-2S^-1)*(2 mol.L^-1)^2*(3mol.L^-1)
The rate of a reaction is = 0.12 mol.L^-1.S^-1
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