MATHYHUU64
MATHYHUU64 MATHYHUU64
  • 18-05-2018
  • Mathematics
contestada

The solution to 15 a2 − 1 = 5 2a − 2 is a = . The extraneous solution is a = .

Respuesta :

carlosego
carlosego carlosego
  • 28-05-2018
For this case the correct expression is:
 15 / (a ^ 2 - 1) = 5 / (2a - 2)
 Rewriting we have:
 3 / (a ^ 2 - 1) = 1/2 (a - 1)
 6 / (a ^ 2 - 1) = 1 / (a - 1)
 6 (a - 1) = (a ^ 2 - 1)
 6 (a - 1) = (a-1) (a + 1)
 (a + 1) = 6
 a = 6-1
 a = 5
 Answer:
 
The solution is:
 
a = 5
Answer Link
somesmurf6969 somesmurf6969
  • 02-06-2020

Answer:

5 and 1

1 is extraneous

Step-by-step explanation:

Answer Link

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