Respuesta :

dalmagro78
[tex]3x^2-2x-8 \geq 0[/tex]

[tex](x-2)(3x+4) \geq 0[/tex]

[tex]3x+4\geq 0 \mbox{ and } x-2\geq 0[/tex]

[tex]x\leq -\frac{4}{3} \mbox{ or } x\geq 2[/tex]

the complement of this set is:

[tex]-\frac{4}{3} \ \textless \ x \ \textless \ 2[/tex]




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